useConsistentArrayType
Diagnostic Category: lint/style/useConsistentArrayType
Since: v1.5.0
Sources:
- Same as:
@typescript-eslint/array-type
Require consistently using either T[]
or Array<T>
TypeScript provides two equivalent ways to define an array type: T[]
and Array<T>
.
The two styles are functionally equivalent.
Using the same style consistently across your codebase makes it easier for developers to read and understand array types.
Example
Section titled ExampleInvalid
Section titled Invalidcode-block.ts:1:14 lint/style/useConsistentArrayType FIXABLE ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
⚠ Use shorthand T[] syntax instead of Array<T> syntax.
> 1 │ let invalid: Array<foo>;
│ ^^^^^^^^^^
2 │
ℹ Unsafe fix: Use shorthand T[] syntax to replace
1 │ - let·invalid:·Array<foo>;
1 │ + let·invalid:·foo[];
2 2 │
code-block.ts:1:22 lint/style/useConsistentArrayType FIXABLE ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
⚠ Use shorthand T[] syntax instead of Array<T> syntax.
> 1 │ let invalid: Promise<Array<string>>;
│ ^^^^^^^^^^^^^
2 │
ℹ Unsafe fix: Use shorthand T[] syntax to replace
1 │ - let·invalid:·Promise<Array<string>>;
1 │ + let·invalid:·Promise<string[]>;
2 2 │
code-block.ts:1:15 lint/style/useConsistentArrayType FIXABLE ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
⚠ Use shorthand T[] syntax instead of Array<T> syntax.
> 1 │ let invalid3: Array<Foo<Bar>>;
│ ^^^^^^^^^^^^^^^
2 │
ℹ Unsafe fix: Use shorthand T[] syntax to replace
1 │ - let·invalid3:·Array<Foo<Bar>>;
1 │ + let·invalid3:·Foo<Bar>[];
2 2 │
Valid
Section titled ValidOptions
Section titled OptionsUse the options to specify the syntax of array declarations to use.
syntax
Section titled syntaxThe syntax to use:
generic
: array declarations will be converted toArray<T>
orReadonlyArray<T>
shorthand
: array declarations will be converted toT[]
orreadonly T[]
Default: shorthand